- a) $$\frac{3}{14}+\left(\frac{2}{7}+\frac{1}{2}\right)=\frac{3}{14}+\left(\frac{2 \cdot 2}{7 \cdot 2}+\frac{1 \cdot 7}{2 \cdot 7}\right)=\frac{3}{14}+\left(\frac{4}{14}+\frac{7}{14}\right)=\frac{3}{14}+\frac{11}{14}=\frac{3+11}{14}=\frac{14}{14}=1$$
- б) $$\frac{11}{56}+\left(\frac{6}{7}-\frac{3}{8}\right)=\frac{11}{56}+\left(\frac{6 \cdot 8}{7 \cdot 8}-\frac{3 \cdot 7}{8 \cdot 7}\right)=\frac{11}{56}+\left(\frac{48}{56}-\frac{21}{56}\right)=\frac{11}{56}+\frac{27}{56}=\frac{11+27}{56}=\frac{38}{56}=\frac{19}{28}$$
- в) $$\left(\frac{5}{8}+\frac{1}{6}\right)-\frac{7}{24}=\left(\frac{5 \cdot 3}{8 \cdot 3}+\frac{1 \cdot 4}{6 \cdot 4}\right)-\frac{7}{24}=\left(\frac{15}{24}+\frac{4}{24}\right)-\frac{7}{24}=\frac{19}{24}-\frac{7}{24}=\frac{19-7}{24}=\frac{12}{24}=\frac{1}{2}$$
- г) $$\frac{15}{36}-\left(\frac{1}{3}-\frac{1}{12}\right)=\frac{15}{36}-\left(\frac{1 \cdot 4}{3 \cdot 4}-\frac{1}{12}\right)=\frac{15}{36}-\left(\frac{4}{12}-\frac{1}{12}\right)=\frac{15}{36}-\frac{3}{12}=\frac{15}{36}-\frac{3 \cdot 3}{12 \cdot 3}=\frac{15}{36}-\frac{9}{36}=\frac{15-9}{36}=\frac{6}{36}=\frac{1}{6}$$
Ответ: a) 1; б) 19/28; в) 1/2; г) 1/6