2. Найдите значение выражения: А) \(\frac{11}{50}-\frac{3}{25}+\frac{1}{20}\); Б) \(8-3\frac{6}{7}\); В) \(2\frac{1}{8}+3\frac{5}{12}\); Г) \(5\frac{13}{15}+1\frac{7}{12}\); Д) \(7\frac{3}{8}-3\frac{5}{6}\).

А) \(\frac{11}{50}-\frac{3}{25}+\frac{1}{20}\)

Приведем дроби к общему знаменателю. Наименьший общий знаменатель для 50, 25 и 20 равен 100.

\(\frac{11}{50} = \frac{11 \cdot 2}{50 \cdot 2} = \frac{22}{100}\)

\(\frac{3}{25} = \frac{3 \cdot 4}{25 \cdot 4} = \frac{12}{100}\)

\(\frac{1}{20} = \frac{1 \cdot 5}{20 \cdot 5} = \frac{5}{100}\)

\(\frac{22}{100}-\frac{12}{100}+\frac{5}{100} = \frac{22-12+5}{100} = \frac{15}{100} = \frac{3}{20}\)

Ответ: \(\frac{3}{20}\)

Б) \(8-3\frac{6}{7}\)

\(8-3\frac{6}{7} = 7\frac{7}{7}-3\frac{6}{7} = (7-3)+(\frac{7}{7}-\frac{6}{7}) = 4+\frac{1}{7} = 4\frac{1}{7}\)

Ответ: \(4\frac{1}{7}\)

В) \(2\frac{1}{8}+3\frac{5}{12}\)

\(2\frac{1}{8}+3\frac{5}{12} = 2\frac{3}{24}+3\frac{10}{24} = (2+3)+(\frac{3}{24}+\frac{10}{24}) = 5+\frac{13}{24} = 5\frac{13}{24}\)

Ответ: \(5\frac{13}{24}\)

Г) \(5\frac{13}{15}+1\frac{7}{12}\)

\(5\frac{13}{15}+1\frac{7}{12} = 5\frac{52}{60}+1\frac{35}{60} = (5+1)+(\frac{52}{60}+ \frac{35}{60}) = 6+\frac{87}{60} = 6+1\frac{27}{60} = 7\frac{9}{20}\)

Ответ: \(7\frac{9}{20}\)

Д) \(7\frac{3}{8}-3\frac{5}{6}\)

\(7\frac{3}{8}-3\frac{5}{6} = 7\frac{9}{24}-3\frac{20}{24} = 6\frac{33}{24}-3\frac{20}{24} = (6-3)+(\frac{33}{24}-\frac{20}{24}) = 3+\frac{13}{24} = 3\frac{13}{24}\)

Ответ: \(3\frac{13}{24}\)