Вопрос:

Найдите сумму: а) \(4\frac{2}{9}+3\frac{5}{18}\); б) \(3\frac{5}{12}+4\frac{7}{9}\); в) \(7\frac{11}{12}+1\frac{3}{8}\); г) \(4\frac{3}{8}+2\frac{4}{11}\); д) \(6\frac{5}{11}+5\); е) \(7\frac{3}{7}+\frac{5}{21}\); ж) \(6+4\frac{2}{7}\); з) \(\frac{3}{7}+3\frac{4}{5}\).

Ответ:

  1. \(4\frac{2}{9}+3\frac{5}{18}=7+\frac{4}{18}+\frac{5}{18}=7\frac{9}{18}=7\frac{1}{2}\).
  2. \(3\frac{5}{12}+4\frac{7}{9}=7+\frac{15}{36}+\frac{28}{36}=7\frac{43}{36}=8\frac{7}{36}\).
  3. \(7\frac{11}{12}+1\frac{3}{8}=8+\frac{22}{24}+\frac{9}{24}=8\frac{31}{24}=9\frac{7}{24}\).
  4. \(4\frac{3}{8}+2\frac{4}{11}=6+\frac{33}{88}+\frac{32}{88}=6\frac{65}{88}\).
  5. \(6\frac{5}{11}+5=11\frac{5}{11}\).
  6. \(7\frac{3}{7}+\frac{5}{21}=7+\frac{9}{21}+\frac{5}{21}=7\frac{14}{21}=7\frac{2}{3}\).
  7. \(6+4\frac{2}{7}=10\frac{2}{7}\).
  8. \(\frac{3}{7}+3\frac{4}{5}=3+\frac{15}{35}+\frac{28}{35}=3\frac{43}{35}=4\frac{8}{35}\).

Ответ: а) \(7\frac{1}{2}\); б) \(8\frac{7}{36}\); в) \(9\frac{7}{24}\); г) \(6\frac{65}{88}\); д) \(11\frac{5}{11}\); е) \(7\frac{2}{3}\); ж) \(10\frac{2}{7}\); з) \(4\frac{8}{35}\).