Найдите сумму:
1) \[\frac{3}{9} + \frac{5}{6} = \frac{1}{3} + \frac{5}{6} = \frac{2 + 5}{6} = \frac{7}{6} = 1\frac{1}{6}\]
3) \(6\frac{8}{12} + 9\frac{7}{18} = 6\frac{2}{3} + 9\frac{7}{18} = 6\frac{12}{18} + 9\frac{7}{18} = 15\frac{19}{18} = 16\frac{1}{18}\)