The problem describes a triangle ABC where \( \angle BAC = 29^{\circ} \), \( BC = 2 \), and \( \angle ACB = 29^{\circ} \).
We observe that \( \angle BAC = \angle ACB = 29^{\circ} \). In a triangle, if two angles are equal, then the sides opposite to these angles are also equal. This means that the side opposite \( \angle BAC \) (which is BC) is equal to the side opposite \( \angle ACB \) (which is AB).
Therefore, since \( BC = 2 \), it follows that \( AB = 2 \).
Ответ: AB = 2.