г) $$\frac{d}{\sqrt{d} + 7} + \frac{14\sqrt{d} + 49}{\sqrt{d} + 7} = \frac{d + 14\sqrt{d} + 49}{\sqrt{d} + 7} = \frac{(\sqrt{d} + 7)^2}{\sqrt{d} + 7} = \sqrt{d} + 7$$.
Ответ: $$\sqrt{d} + 7$$