Решение:
\( \frac{4}{8} - \frac{1}{8} \)
\( = \frac{4-1}{8} = \frac{3}{8} \)
\( \frac{1}{7} + \frac{3}{7} \)
\( = \frac{1+3}{7} = \frac{4}{7} \)
\( \frac{4}{5} - \frac{1}{5} \)
\( = \frac{4-1}{5} = \frac{3}{5} \)
\( \frac{7}{10} - \frac{1}{10} \)
\( = \frac{7-1}{10} = \frac{6}{10} = \frac{3}{5} \)
\( \frac{2}{4} - \frac{1}{4} \)
\( = \frac{2-1}{4} = \frac{1}{4} \)
\( \frac{1}{3} + \frac{1}{5} \)
\( = \frac{1 \times 5}{3 \times 5} + \frac{1 \times 3}{5 \times 3} = \frac{5}{15} + \frac{3}{15} = \frac{5+3}{15} = \frac{8}{15} \)
Ответ: \( \frac{3}{8} \), \( \frac{4}{7} \), \( \frac{3}{5} \), \( \frac{3}{5} \), \( \frac{1}{4} \), \( \frac{8}{15} \).