е) (2\(\frac{2}{7}\) + 1\(\frac{1}{7}\)) * 1\(\frac{1}{6}\) = (\(\frac{16}{7}\) + \(\frac{8}{7}\)) * \(\frac{7}{6}\) = (\(\frac{16+8}{7}\)) * \(\frac{7}{6}\) = (\(\frac{24}{7}\)) * \(\frac{7}{6}\) = (\(\frac{24*7}{7*6}\)) = \(\frac{168}{42}\) = 4
Ответ: 4