Dy: 1) f(x) = 2x³-1 f(0)-? 2) f(x)=\frac{4}{2x+1} f (3) -? 3) f(x)=\frac{1}{2} x-5 f(4)-?

1) f(x) = 2x³-1

Найдем f(0):

f(0) = 2 * 0³ - 1 = 2 * 0 - 1 = 0 - 1 = -1

2) f(x) = \frac{4}{2x+1}

Найдем f(3):

f(3) = \frac{4}{2*3+1} = \frac{4}{6+1} = \frac{4}{7}

3) f(x) = \frac{1}{2}x - 5

Найдем f(4):

f(4) = \frac{1}{2} * 4 - 5 = 2 - 5 = -3