The Problem
We are given a right-angled triangle with vertices labeled M, B, and C. The right angle is at vertex C. We need to express the sine, cosine, and tangent of angles M and B.
Solution
Let's denote the lengths of the sides opposite to angles M, B, and C as $$m$$, $$b$$, and $$c$$ respectively. In a right-angled triangle:
- The side opposite the right angle is the hypotenuse.
- The side opposite an angle is the opposite side.
- The side adjacent to an angle (that is not the hypotenuse) is the adjacent side.
In our triangle:
- The hypotenuse is the side opposite to the right angle C, which is side $$MB$$.
- For angle M:
- Opposite side is $$BC$$ (length $$m$$).
- Adjacent side is $$MC$$ (length $$b$$).
- Hypotenuse is $$MB$$ (length $$c$$).
- For angle B:
- Opposite side is $$MC$$ (length $$b$$).
- Adjacent side is $$BC$$ (length $$m$$).
- Hypotenuse is $$MB$$ (length $$c$$).
The trigonometric ratios are defined as:
- Sine (sin) = Opposite / Hypotenuse
- Cosine (cos) = Adjacent / Hypotenuse
- Tangent (tan) = Opposite / Adjacent
Trigonometric Functions for Angle M:
- sin M = Opposite / Hypotenuse = $$\frac{BC}{MB}$$ = $$\frac{m}{c}$$
- cos M = Adjacent / Hypotenuse = $$\frac{MC}{MB}$$ = $$\frac{b}{c}$$
- tg M = Opposite / Adjacent = $$\frac{BC}{MC}$$ = $$\frac{m}{b}$$
Trigonometric Functions for Angle B:
- sin B = Opposite / Hypotenuse = $$\frac{MC}{MB}$$ = $$\frac{b}{c}$$
- cos B = Adjacent / Hypotenuse = $$\frac{BC}{MB}$$ = $$\frac{m}{c}$$
- tg B = Opposite / Adjacent = $$\frac{MC}{BC}$$ = $$\frac{b}{m}$$
Summary from the image:
The image provides the setup for these calculations, indicating the labels for angles and sides, and prompts for the trigonometric functions.
Final Answer:
sin M = $$\frac{m}{c}$$, cos M = $$\frac{b}{c}$$, tg M = $$\frac{m}{b}$$
sin B = $$\frac{b}{c}$$, cos B = $$\frac{m}{c}$$, tg B = $$\frac{b}{m}$$
(Where $$m$$ is the length of side BC, $$b$$ is the length of side MC, and $$c$$ is the length of the hypotenuse MB)