25\(\frac{5}{3}\) - \(\frac{4}{5}\) = \(\frac{25 \cdot 3 + 5}{3}\) - \(\frac{4}{5}\) = \(\frac{75 + 5}{3}\) - \(\frac{4}{5}\) = \(\frac{80}{3}\) - \(\frac{4}{5}\) = \(\frac{80 \cdot 5 - 4 \cdot 3}{3 \cdot 5}\) = \(\frac{400 - 12}{15}\) = \(\frac{388}{15}\) = 25\(\frac{13}{15}\)
10\(\frac{8}{2}\) - \(\frac{15}{4}\) = \(\frac{10 \cdot 2 + 8}{2}\) - \(\frac{15}{4}\) = \(\frac{20 + 8}{2}\) - \(\frac{15}{4}\) = \(\frac{28}{2}\) - \(\frac{15}{4}\) = \(\frac{28 \cdot 2 - 15}{4}\) = \(\frac{56 - 15}{4}\) = \(\frac{41}{4}\) = 10\(\frac{1}{4}\)
13\(\frac{9}{8}\) - \(\frac{4}{3}\) = \(\frac{13 \cdot 8 + 9}{8}\) - \(\frac{4}{3}\) = \(\frac{104 + 9}{8}\) - \(\frac{4}{3}\) = \(\frac{113}{8}\) - \(\frac{4}{3}\) = \(\frac{113 \cdot 3 - 4 \cdot 8}{8 \cdot 3}\) = \(\frac{339 - 32}{24}\) = \(\frac{307}{24}\) = 12\(\frac{19}{24}\)
30\(\frac{7}{5}\) - \(\frac{8}{3}\) = \(\frac{30 \cdot 5 + 7}{5}\) - \(\frac{8}{3}\) = \(\frac{150 + 7}{5}\) - \(\frac{8}{3}\) = \(\frac{157}{5}\) - \(\frac{8}{3}\) = \(\frac{157 \cdot 3 - 8 \cdot 5}{5 \cdot 3}\) = \(\frac{471 - 40}{15}\) = \(\frac{431}{15}\) = 28\(\frac{11}{15}\)
5\(\frac{4}{3}\) - \(\frac{8}{5}\) = \(\frac{5 \cdot 3 + 4}{3}\) - \(\frac{8}{5}\) = \(\frac{15 + 4}{3}\) - \(\frac{8}{5}\) = \(\frac{19}{3}\) - \(\frac{8}{5}\) = \(\frac{19 \cdot 5 - 8 \cdot 3}{3 \cdot 5}\) = \(\frac{95 - 24}{15}\) = \(\frac{71}{15}\) = 4\(\frac{11}{15}\)
21\(\frac{2}{1}\) - \(\frac{14}{5}\) = \(\frac{21 \cdot 1 + 2}{1}\) - \(\frac{14}{5}\) = \(\frac{21 + 2}{1}\) - \(\frac{14}{5}\) = \(\frac{23}{1}\) - \(\frac{14}{5}\) = \(\frac{23 \cdot 5 - 14}{5}\) = \(\frac{115 - 14}{5}\) = \(\frac{101}{5}\) = 20\(\frac{1}{5}\)
8\(\frac{5}{4}\) - \(\frac{12}{15}\) = \(\frac{8 \cdot 4 + 5}{4}\) - \(\frac{12}{15}\) = \(\frac{32 + 5}{4}\) - \(\frac{12}{15}\) = \(\frac{37}{4}\) - \(\frac{12}{15}\) = \(\frac{37 \cdot 15 - 12 \cdot 4}{4 \cdot 15}\) = \(\frac{555 - 48}{60}\) = \(\frac{507}{60}\) = 8\(\frac{27}{60}\) = 8\(\frac{9}{20}\)
1\(\frac{4}{3}\) - \(\frac{7}{11}\) = \(\frac{1 \cdot 3 + 4}{3}\) - \(\frac{7}{11}\) = \(\frac{3 + 4}{3}\) - \(\frac{7}{11}\) = \(\frac{7}{3}\) - \(\frac{7}{11}\) = \(\frac{7 \cdot 11 - 7 \cdot 3}{3 \cdot 11}\) = \(\frac{77 - 21}{33}\) = \(\frac{56}{33}\) = 1\(\frac{23}{33}\)
Ответ: решения выше
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