Вопрос:

Complete the table with the calculations.

Смотреть решения всех заданий с листа

Ответ:

Решение:

Заполним таблицу, выполняя вычисления для каждого ячейки.

1.11.21.31.41.5
1\(1 - \frac{2}{7} = \frac{5}{7}\)\(2 \cdot \frac{1}{4} = \frac{1}{2}\)\(1 - \frac{5}{6} = \frac{1}{6}\)\(8 \cdot \frac{7}{8} = 7\)\(\frac{3}{4} : \frac{4}{3} = \frac{3}{4} \cdot \frac{3}{4} = \frac{9}{16}\)
2\(1 + \frac{2}{7} = \frac{9}{7}\)\(2 : \frac{1}{2} = 4\)\(2 - \frac{5}{6} = \frac{7}{6}\)\(\frac{3}{8} : \frac{8}{3} = \frac{3}{8} \cdot \frac{3}{8} = \frac{9}{64}\)\(\frac{3}{3} : \frac{4}{4} = 1\)
3\(1 \cdot \frac{2}{7} = \frac{2}{7}\)\(2 + \frac{1}{4} = \frac{9}{4}\)\(10 - 3 \frac{5}{6} = 6 \frac{1}{6}\)\(1 \cdot \frac{3}{8} = \frac{3}{8}\)\(\frac{3}{4} + \frac{3}{4} = \frac{6}{4} = \frac{3}{2}\)
4\(\frac{3}{4} - \frac{4}{3} = \frac{9 - 16}{12} = -\frac{7}{12}\)\(2 - \frac{1}{4} = \frac{7}{4}\)\(-2 + \frac{3}{4} = -\frac{5}{4}\)\(1 - \frac{3}{8} = \frac{5}{8}\)\(\frac{3}{3} : \frac{4}{4} = 1\)
5\(-\frac{2}{5} + 2 = \frac{8}{5}\)\(-2 - \frac{1}{4} = -\frac{9}{4}\)\(-2 - \frac{3}{4} = -\frac{11}{4}\)\(1 + \frac{3}{8} = \frac{11}{8}\)\(\frac{3}{4} + \frac{3}{4} = \frac{6}{4} = \frac{3}{2}\)
6\(\frac{2}{5} - 2 = -\frac{8}{5}\)\(-5 \cdot \left(-\frac{2}{5}\right) = 2\)\(-2 \cdot \frac{3}{4} = -\frac{3}{2}\)\(-5 + 4 \frac{1}{5} = -\frac{4}{5}\)\(5 - 2 \frac{1}{3} = 2 \frac{2}{3}\)
7\(3 \frac{1}{2} \cdot 2 = 7\)\(-5 : \frac{2}{5} = -5 \cdot \frac{5}{2} = -\frac{25}{2}\)\(-2 : \left(\frac{3}{4}\right) = -2 \cdot \frac{4}{3} = -\frac{8}{3}\)\(-5 - 4 \frac{1}{5} = -9 \frac{1}{5}\)\(5 - 6 \frac{1}{3} = -1 \frac{1}{3}\)
8\(3 \frac{1}{2} : 2 = \frac{7}{2} : 2 = \frac{7}{4}\)\(5 - 2 \frac{2}{5} = 2 \frac{3}{5}\)\(-3 \frac{1}{2} + \frac{1}{2} = -3\)\(5 \cdot \left(-4 \frac{1}{5}\right) = 5 \cdot \left(-\frac{21}{5}\right) = -21\)\(-5 - 6 \frac{1}{3} = -11 \frac{1}{3}\)
9\(-4 + 2 \frac{1}{2} = -1 \frac{1}{2}\)\(5 - 2 \frac{2}{5} = 2 \frac{3}{5}\)\(-3 \frac{1}{2} \cdot \frac{1}{2} = -\frac{7}{2} \cdot \frac{1}{2} = -\frac{7}{4}\)\(5 : \left(-\frac{4}{5}\right) = 5 \cdot \left(-\frac{5}{4}\right) = -\frac{25}{4}\)\(-5 \cdot 1 \frac{1}{2} = -5 \cdot \frac{3}{2} = -\frac{15}{2}\)
10\(-4 - 2 \frac{1}{2} = -6 \frac{1}{2}\)\(-5 - 2 \frac{2}{5} = -7 \frac{2}{5}\)\(3 \frac{1}{2} \cdot 2 = 7\)\(-1 \frac{1}{2} + 4 = 2 \frac{1}{2}\)\(-5 : 1 \frac{1}{2} = -5 : \frac{3}{2} = -5 \cdot \frac{2}{3} = -\frac{10}{3}\)
11\(5 : 1 \frac{1}{2} = 5 : \frac{3}{2} = 5 \cdot \frac{2}{3} = \frac{10}{3}\)\(-5 + 2 \frac{2}{5} = -2 \frac{3}{5}\)\(1 \frac{1}{2} : \frac{1}{4} = \frac{3}{2} : \frac{1}{4} = \frac{3}{2} \cdot 4 = 6\)\(-1 \frac{1}{2} - 4 = -5 \frac{1}{2}\)\(-4 \cdot \frac{1}{12} = -\frac{4}{12} = -\frac{1}{3}\)
12\(2 \frac{1}{2} : 5 = \frac{5}{2} : 5 = \frac{1}{2}\)\(\frac{2}{7} \cdot 3 \frac{1}{2} = \frac{2}{7} \cdot \frac{7}{2} = 1\)\(-\frac{1}{3} \cdot 6 = -2\)\(-4 : \left(\frac{1}{12}\right) = -4 \cdot 12 = -48\)\(-4 + \frac{1}{12} = -3 \frac{11}{12}\)
13\(1 : \frac{1}{4} = 4\)\(\frac{3}{7} \cdot \frac{4}{7} = \frac{12}{49}\)\(-14 \cdot \left(-\frac{1}{7}\right) = 2\)\(1 \frac{1}{2} \cdot 4 = \frac{3}{2} \cdot 4 = 6\)\(-4 + \frac{1}{12} = -3 \frac{11}{12}\)
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