б) \(\frac{3m+1}{3m^2-27n^2}\), \(\frac{3m+9n}{2+6n}\)

б) Упростим выражение:

$$ \frac{3m+1}{3m^2-27n^2} \div \frac{3m+9n}{2+6n} $$

$$ = \frac{3m+1}{3(m^2-9n^2)} \div \frac{3(m+3n)}{2(1+3n)} $$

$$ = \frac{3m+1}{3(m-3n)(m+3n)} \times \frac{2(1+3n)}{3(m+3n)} $$

$$ = \frac{(3m+1) \times 2(1+3n)}{3(m-3n)(m+3n) \times 3(m+3n)} $$

$$ = \frac{2(3m+1)(3n+1)}{9(m-3n)(m+3n)^2} $$

Ответ: \(\frac{2(3m+1)(3n+1)}{9(m-3n)(m+3n)^2}\)