Краткое пояснение: Применим формулу разности квадратов: (a - b)(a + b) = a² - b².
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\[ (x-y)(x+y) = x^2 - y^2 \]
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\[ (2x-1)(2x+1) = (2x)^2 - 1^2 = 4x^2 - 1 \]
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\[ (8c+9d)(8c-9d) = (8c)^2 - (9d)^2 = 64c^2 - 81d^2 \]
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\[ (1-3k)(1+3k) = 1^2 - (3k)^2 = 1 - 9k^2 \]
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\[ (a^2-3)(a^2+3) = (a^2)^2 - 3^2 = a^4 - 9 \]
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\[ (y-\alpha^2)(y+\alpha^2) = y^2 - (\alpha^2)^2 = y^2 - \alpha^4 \]
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\[ (b^3-c)(b^3+c) = (b^3)^2 - c^2 = b^6 - c^2 \]
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\[ (m^2-p^3)(m^2+p^3) = (m^2)^2 - (p^3)^2 = m^4 - p^6 \]
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\[ (5a^8 - 6x^3)(6x^3 + 5a^8) = (5a^8)^2 - (6x^3)^2 = 25a^{16} - 36x^6 \]
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\[ (5x^2+2y^3)(5x^2-2y^3) = (5x^2)^2 - (2y^3)^2 = 25x^4 - 4y^6 \]
Ответ: См. решение