Add the below mixed fractions

Решение:

1. \( 3\frac{3}{4} + 2\frac{1}{4} = \frac{3+2}{1} + \frac{3+1}{4} = 5 + \frac{4}{4} = 5 + 1 = 6 \)
2. \( 1\frac{4}{8} + 2\frac{1}{8} = \frac{1+2}{1} + \frac{4+1}{8} = 3 + \frac{5}{8} = 3\frac{5}{8} \)
3. \( 5\frac{6}{7} + 4\frac{1}{2} = 5 + 4 + \frac{6 \cdot 2}{7 \cdot 2} + \frac{1 \cdot 7}{2 \cdot 7} = 9 + \frac{12}{14} + \frac{7}{14} = 9 + \frac{19}{14} = 9 + 1\frac{5}{14} = 10\frac{5}{14} \)
4. \( 2\frac{3}{5} + 4\frac{2}{5} = \frac{2+4}{1} + \frac{3+2}{5} = 6 + \frac{5}{5} = 6 + 1 = 7 \)
5. \( 1\frac{5}{9} + 3\frac{1}{9} = \frac{1+3}{1} + \frac{5+1}{9} = 4 + \frac{6}{9} = 4 + \frac{2}{3} = 4\frac{2}{3} \)
6. \( 4\frac{1}{6} + 3\frac{4}{6} = \frac{4+3}{1} + \frac{1+4}{6} = 7 + \frac{5}{6} = 7\frac{5}{6} \)
7. \( 3\frac{1}{4} + 2\frac{4}{6} = 3\frac{3}{12} + 2\frac{8}{12} = \frac{3+2}{1} + \frac{3+8}{12} = 5 + \frac{11}{12} = 5\frac{11}{12} \)
8. \( 5\frac{2}{9} + 1\frac{1}{9} = \frac{5+1}{1} + \frac{2+1}{9} = 6 + \frac{3}{9} = 6 + \frac{1}{3} = 6\frac{1}{3} \)
9. \( 4\frac{1}{8} + 3\frac{2}{4} = 4\frac{1}{8} + 3\frac{4}{8} = \frac{4+3}{1} + \frac{1+4}{8} = 7 + \frac{5}{8} = 7\frac{5}{8} \)
10. \( 3\frac{7}{10} + 2\frac{1}{10} = \frac{3+2}{1} + \frac{7+1}{10} = 5 + \frac{8}{10} = 5 + \frac{4}{5} = 5\frac{4}{5} \)
11. \( 4\frac{4}{9} + 1\frac{2}{9} = \frac{4+1}{1} + \frac{4+2}{9} = 5 + \frac{6}{9} = 5 + \frac{2}{3} = 5\frac{2}{3} \)
12. \( 4\frac{4}{5} + 1\frac{2}{5} = \frac{4+1}{1} + \frac{4+2}{5} = 5 + \frac{6}{5} = 5 + 1\frac{1}{5} = 6\frac{1}{5} \)
13. \( \frac{3}{7} + 1\frac{1}{7} = 1 + \frac{3+1}{7} = 1\frac{4}{7} \)
14. \( 2\frac{1}{3} + 3\frac{2}{3} = \frac{2+3}{1} + \frac{1+2}{3} = 5 + \frac{3}{3} = 5 + 1 = 6 \)
15. \( 5\frac{1}{7} + \frac{2}{7} = 5 + \frac{1+2}{7} = 5\frac{3}{7} \)
16. \( \frac{3}{10} + 2\frac{3}{10} = 2 + \frac{3+3}{10} = 2\frac{6}{10} = 2\frac{3}{5} \)