Исходное уравнение: \( x - \frac{4}{x} = 3 \)
\[ x \cdot x - \frac{4}{x} \cdot x = 3 \cdot x \]
\[ x^2 - 4 = 3x \]
\[ x^2 - 3x - 4 = 0 \]
\[ D = b^2 - 4ac = (-3)^2 - 4 \cdot 1 \cdot (-4) = 9 + 16 = 25 \]
\[ x_1 = \frac{-b + \sqrt{D}}{2a} = \frac{3 + \sqrt{25}}{2 \cdot 1} = \frac{3 + 5}{2} = \frac{8}{2} = 4 \]
\[ x_2 = \frac{-b - \sqrt{D}}{2a} = \frac{3 - \sqrt{25}}{2 \cdot 1} = \frac{3 - 5}{2} = \frac{-2}{2} = -1 \]
Ответ: -1,4