9) (1)9 (1)2 (13)3 =

9) $$\left(\frac{1}{3}\right)^9 \cdot \left(\frac{1}{3}\right)^2 \cdot \left(\frac{1}{3}\right)^3 = \left(\frac{1}{3}\right)^{9+2+3} = \left(\frac{1}{3}\right)^{14} $$

Ответ: $$\left(\frac{1}{3}\right)^{14}$$