Ответ:
Решение:
Выражение: (¬A Ѵ B ∧ ¬C) ∧ A
| A | B | C | ¬A | ¬C | ¬A Ѵ B | (¬A Ѵ B) ∧ ¬C | (¬A Ѵ B ∧ ¬C) ∧ A |
| 0 | 0 | 0 | 1 | 1 | 1 V 0 = 1 | 1 ∧ 1 = 1 | 1 ∧ 0 = 0 |
| 0 | 0 | 1 | 1 | 0 | 1 V 0 = 1 | 1 ∧ 0 = 0 | 0 ∧ 0 = 0 |
| 0 | 1 | 0 | 1 | 1 | 1 V 1 = 1 | 1 ∧ 1 = 1 | 1 ∧ 0 = 0 |
| 0 | 1 | 1 | 1 | 0 | 1 V 1 = 1 | 1 ∧ 0 = 0 | 0 ∧ 0 = 0 |
| 1 | 0 | 0 | 0 | 1 | 0 V 0 = 0 | 0 ∧ 1 = 0 | 0 ∧ 1 = 0 |
| 1 | 0 | 1 | 0 | 0 | 0 V 0 = 0 | 0 ∧ 0 = 0 | 0 ∧ 1 = 0 |
| 1 | 1 | 0 | 0 | 1 | 0 V 1 = 1 | 1 ∧ 1 = 1 | 1 ∧ 1 = 1 |
| 1 | 1 | 1 | 0 | 0 | 0 V 1 = 1 | 1 ∧ 0 = 0 | 0 ∧ 1 = 0 |
Ответ:
| A | B | C | |
| 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 0 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 0 |
| 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 1 |
| 1 | 1 | 1 | 0 |
