Решение:
\[ \frac{7b^2}{a^2-9} : \frac{7b}{a+3} = \frac{7b^2}{a^2-9} \times \frac{a+3}{7b} \]
\[ = \frac{7b^2 · (a+3)}{(a-3)(a+3) · 7b} \]
\[ = \frac{b}{a-3} \]
\[ \frac{6}{5-3} = \frac{6}{2} = 3 \]
Ответ: 3