7) \(\frac{4}{33}\cdot\frac{121}{14}:\frac{55}{42}\cdot3=\)

\[\frac{4}{33}\cdot\frac{121}{14}:\frac{55}{42}\cdot3=\frac{4}{33}\cdot\frac{121}{14}\cdot\frac{42}{55}\cdot3=12\]

Ответ: 12