61.(+).

61. $$(\frac{5}{12} + \frac{3}{8}) \cdot \frac{6}{19} = (\frac{5 \cdot 2}{12 \cdot 2} + \frac{3 \cdot 3}{8 \cdot 3}) \cdot \frac{6}{19} = (\frac{10}{24} + \frac{9}{24}) \cdot \frac{6}{19} = \frac{19}{24} \cdot \frac{6}{19} = \frac{19 \cdot 6}{24 \cdot 19} = \frac{1 \cdot 1}{4 \cdot 1} = \frac{1}{4}$$

Ответ: $$\frac{1}{4}$$