Разложение на множители:
- \( 9(b-1)+(b-1) = (b-1)(9+1) = 10(b-1) \)
- \( 3a(2x-7)+b(7-2x) = 3a(2x-7)-b(2x-7) = (2x-7)(3a-b) \)
- \( (x-y)^2 - a(y-x) = (x-y)^2 + a(x-y) = (x-y)(x-y+a) \)
- \( 2(3-b)+5(b-3)^2 = -2(b-3)+5(b-3)^2 = (b-3)(-2+5(b-3)) = (b-3)(-2+5b-15) = (b-3)(5b-17) \)
Ответ: 4) \( 10(b-1) \); 9) \( (2x-7)(3a-b) \); 10) \( (x-y)(x-y+a) \); 12) \( (b-3)(5b-17) \).