6. \(\left(\left(\frac38-\frac56\right):\frac34+\left(-\frac38-0,35\right):1,45\right)\cdot0,02\)

Преобразуем десятичные дроби: \(0,35=\frac7{20}\), \(1,45=\frac{29}{20}\), \(0,02=\frac1{50}\).

\(\left(\frac38-\frac56\right):\frac34=\left(-\frac{11}{24}\right):\frac34=-\frac{11}{18}\).

\(\left(-\frac38-\frac7{20}\right):\frac{29}{20}=\left(-\frac{29}{40}\right):\frac{29}{20}=-\frac12\).

Сумма в скобках:

\(-\frac{11}{18}-\frac12=-\frac{11}{18}-\frac9{18}=-\frac{10}{9}\).

\(-\frac{10}{9}\cdot\frac1{50}=-\frac1{45}\).

Ответ: \(-\frac1{45}\).