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МатематикаВопрос:
5) \(\frac{5}{16}\) : 3 = \(\frac{5}{48}\) \(\frac{7}{25}\) : 2 = \(\frac{7}{50}\) \(\frac{3}{4}\) : 16 = \(\frac{3}{64}\)
Ответ:
Решение:
Примеры на деление дроби на число:
- \(\frac{5}{16} : 3 = \frac{5}{16 \times 3} = \frac{5}{48}\)
- \(\frac{7}{25} : 2 = \frac{7}{25 \times 2} = \frac{7}{50}\)
- \(\frac{3}{4} : 16 = \frac{3}{4 \times 16} = \frac{3}{64}\)
Ответ: \(\frac{5}{48}\), \(\frac{7}{50}\), \(\frac{3}{64}\).
Похожие
- 1) \(\frac{4}{6}\) : \(\frac{1}{2}\) = \(\frac{4}{3}\) \(\frac{3}{5}\) : \(\frac{1}{5}\) = 3 \(\frac{7}{10}\) : \(\frac{4}{10}\) = \(\frac{7}{4}\) \(\frac{4}{5}\) : \(\frac{2}{5}\) = 2 \(\frac{8}{15}\) : \(\frac{4}{15}\) = 2
- 2) \(\frac{2}{3}\) : \(\frac{1}{6}\) = 4 \(\frac{5}{7}\) : \(\frac{1}{7}\) = 35 \(\frac{4}{5}\) : \(\frac{1}{5}\) = 20 \(\frac{3}{4}\) : \(\frac{1}{4}\) = 3 \(\frac{5}{12}\) : \(\frac{1}{12}\) = 5
- 3) \(1\frac{1}{2}\) : \(\frac{1}{2}\) = 3 \(\frac{2}{5}\) : \(\frac{1}{7}\) = \(\frac{14}{5}\) 3 \(\frac{3}{4}\) : \(\frac{1}{5}\) = \(\frac{75}{4}\) \(\frac{1}{3}\) : \(\frac{1}{2}\) = \(\frac{2}{3}\) \(\frac{4}{5}\) : \(\frac{2}{3}\) = \(\frac{6}{5}\)
- 4) \(\frac{25}{36}\) : \(\frac{5}{18}\) = \(\frac{50}{27}\) \(\frac{27}{50}\) : \(\frac{9}{10}\) = \(\frac{3}{5}\) \(\frac{21}{72}\) : \(\frac{3}{4}\) = \(\frac{7}{24}\) \(\frac{45}{49}\) : \(\frac{15}{21}\) = \(\frac{21}{7}\) \(\frac{18}{24}\) : \(\frac{3}{4}\) = \(\frac{3}{4}\)
- 1) \(\frac{3}{5}\) : \(\frac{1}{6}\) = \(\frac{18}{5}\) \(\frac{43}{10}\) : \(\frac{1}{5}\) = \(\frac{43}{2}\) \(\frac{7}{8}\) : \(\frac{1}{7}\) = \(\frac{49}{8}\)
- 2) \(\frac{3}{8}\) : 16 = \(\frac{3}{128}\) 2 \(\frac{5}{6}\) : \(\frac{1}{4}\) = \(\frac{70}{9}\) 27 \(\frac{4}{9}\) : \(\frac{2}{5}\) = \(\frac{1215}{18}\)
- 3) 2 \(\frac{1}{6}\) : 3 = \(\frac{13}{18}\) 2 \(\frac{2}{5}\) : \(\frac{1}{5}\) = 12 2 \(\frac{1}{5}\) : 0 = неопределённость
- 4) \(1\frac{1}{4}\) : \(\frac{2}{5}\) = \(\frac{25}{8}\) \(3\frac{1}{2}\) : \(\frac{4}{3}\) = \(\frac{21}{8}\) \(12\frac{1}{3}\) : \(\frac{3}{5}\) = \(\frac{190}{9}\)
- TOK + KOT + TOK = ?
