á) 5 - \(1,5δ + \frac{1}{3}\) \(\cdot\) 6 = 2\(\frac{1}{3}\)δ - 5\(\frac{1}{2}\)

Решение:

1. \( 5 - (\frac{3}{2} \delta + \frac{1}{3}) \cdot 6 = \frac{7}{3} \delta - \frac{11}{2} \)
2. \( 5 - (\frac{3}{2} \delta \cdot 6 + \frac{1}{3} \cdot 6) = \frac{7}{3} \delta - \frac{11}{2} \)
3. \( 5 - (9\delta + 2) = \frac{7}{3} \delta - \frac{11}{2} \)
4. \( 5 - 9\delta - 2 = \frac{7}{3} \delta - \frac{11}{2} \)
5. \( 3 - 9\delta = \frac{7}{3} \delta - \frac{11}{2} \)
6. \( 3 + \frac{11}{2} = \frac{7}{3} \delta + 9\delta \)
7. \( \frac{6+11}{2} = \delta (\frac{7}{3} + 9) \)
8. \( \frac{17}{2} = \delta (\frac{7+27}{3}) \)
9. \( \frac{17}{2} = \frac{34}{3} \delta \)
10. \( \delta = \frac{17}{2} \cdot \frac{3}{34} \)
11. \( \delta = \frac{1}{2} \cdot \frac{3}{2} \)
12. \( \delta = \frac{3}{4} \)

Ответ: \( \delta = \frac{3}{4} \).