а) \(3\frac{3}{5}+\frac{1}{5}=3\frac{4}{5}\); б) \(4\frac{3}{7}+2\frac{4}{7}=6\frac{7}{7}=7\); в) \(3\frac{5}{6}+\frac{1}{6}=3\frac{6}{6}=4\); г) \(15\frac{3}{8}+4\frac{2}{8}=19\frac{5}{8}\); д) \(\frac{7}{11}+3\frac{2}{11}=3\frac{9}{11}\); е) \(9\frac{3}{10}+4\frac{1}{10}=13\frac{4}{10}=13\frac{2}{5}\); ж) \(17\frac{5}{12}+1\frac{7}{12}=18\frac{12}{12}=19\); з) \(\frac{1}{9}+9\frac{8}{9}=9\frac{9}{9}=10\).
Ответ: а) \(3\frac{4}{5}\); б) \(7\); в) \(4\); г) \(19\frac{5}{8}\); д) \(3\frac{9}{11}\); е) \(13\frac{2}{5}\); ж) \(19\); з) \(10\).