3. Найдите разность:

Решение:

1. \( 3\frac{1}{5} - 1\frac{1}{5} = (3-1) + (\frac{1}{5} - \frac{1}{5}) = 2 + 0 = 2 \)
2. \( 3\frac{4}{5} - 1\frac{1}{5} = \frac{19}{5} - \frac{6}{5} = \frac{13}{5} = 2\frac{3}{5} \)
3. \( 4\frac{2}{7} - 2\frac{4}{7} = (3+1)\frac{2}{7} - 2\frac{4}{7} = 3\frac{9}{7} - 2\frac{4}{7} = (3-2) + (\frac{9}{7} - \frac{4}{7}) = 1 + \frac{5}{7} = 1\frac{5}{7} \)
4. \( 4\frac{2}{7} - 2\frac{4}{7} = \frac{30}{7} - \frac{18}{7} = \frac{12}{7} = 1\frac{5}{7} \)
5. \( 5\frac{2}{13} - 4\frac{5}{13} = 4\frac{15}{13} - 4\frac{5}{13} = (4-4) + (\frac{15}{13} - \frac{5}{13}) = \frac{10}{13} \)
6. \( 5\frac{2}{13} - 4\frac{5}{13} = \frac{67}{13} - \frac{57}{13} = \frac{10}{13} \)
7. \( 3\frac{4}{15} - 1\frac{7}{15} = \frac{49}{15} - \frac{22}{15} = \frac{27}{15} = 1\frac{12}{15} = 1\frac{4}{5} \)