№ 3. Начертите на координатной плоскости треугольник АВС, если А(3; -4), В(1; 4), C(-3; -2). Найдите координаты точек пересечения стороны АВ с осью х и стороны АС с осью у.

1. The equation of line AB passing through A(3, -4) and B(1, 4) is y - 4 = ((4 - (-4))/(1 - 3)) * (x - 1), which simplifies to y - 4 = -4(x - 1), or y = -4x + 8. To find the x-intercept, set y = 0: 0 = -4x + 8, so x = 2. The x-intercept is (2, 0).
2. The equation of line AC passing through A(3, -4) and C(-3, -2) is y - (-4) = ((-2 - (-4))/(-3 - 3)) * (x - 3), which simplifies to y + 4 = (2/-6) * (x - 3), or y + 4 = (-1/3)(x - 3). To find the y-intercept, set x = 0: y + 4 = (-1/3)(-3), so y + 4 = 1, which means y = -3. The y-intercept is (0, -3).