\[\frac{11}{28}:\frac{2}{5}\cdot\frac{16}{55}=\frac{11}{28}\cdot\frac{5}{2}\cdot\frac{16}{55}\]
Сократим: \(11\) и \(55\), \(16\) и \(28\):
\[\frac{1}{7}\cdot\frac{5}{2}\cdot\frac{4}{5}=\frac{2}{7}\]
Ответ: \(\frac{2}{7}\).