Вопрос:
29. Выполни
Ответ:
Решение:
- \(\frac{7}{12} + \frac{3}{12} = \frac{7+3}{12} = \frac{10}{12} = \frac{5}{6}\)
- \(\frac{3}{7} + \frac{2}{7} = \frac{3+2}{7} = \frac{5}{7}\)
- \(\frac{13}{55} - \frac{5}{55} = \frac{13-5}{55} = \frac{8}{55}\)
- \(\frac{11}{18} - \frac{7}{18} = \frac{11-7}{18} = \frac{4}{18} = \frac{2}{9}\)
- \(\frac{7}{10} + \frac{1}{10} = \frac{7+1}{10} = \frac{8}{10} = \frac{4}{5}\)
- \(\frac{4}{5} - \frac{3}{5} = \frac{4-3}{5} = \frac{1}{5}\)
- \(\frac{4}{11} + \frac{6}{11} = \frac{4+6}{11} = \frac{10}{11}\)
- \(\frac{7}{8} - \frac{5}{8} = \frac{7-5}{8} = \frac{2}{8} = \frac{1}{4}\)
- \(\frac{76}{100} - \frac{67}{100} = \frac{76-67}{100} = \frac{9}{100}\)
- \(\frac{8}{13} - \frac{7}{13} = \frac{8-7}{13} = \frac{1}{13}\)
- \(3 - \frac{4}{7} = \frac{3 \cdot 7 - 4}{7} = \frac{21-4}{7} = \frac{17}{7}\)
- \(1 - \frac{6}{11} = \frac{11-6}{11} = \frac{5}{11}\)
- \(1 + 3\frac{5}{7} = 1 + \frac{3 \cdot 7 + 5}{7} = 1 + \frac{26}{7} = \frac{7+26}{7} = \frac{33}{7}\)
- \(8\frac{2}{5} + 3 = \frac{8 \cdot 5 + 2}{5} + 3 = \frac{42}{5} + \frac{15}{5} = \frac{42+15}{5} = \frac{57}{5}\)