\(\left(5\frac57\cdot\frac38-5\frac14:7\right):3+3\frac3{28}-\frac12\)
\(=\left(\frac{40}{7}\cdot\frac38-\frac{21}{4}:7\right):3+\frac{87}{28}-\frac12\)
\(=\left(\frac{15}{7}-\frac34\right):3+\frac{73}{28}=\frac{23}{28}:3+\frac{73}{28}=\frac{23}{84}+\frac{219}{84}=\frac{121}{42}.\)
\(\left(6\frac14\cdot2\frac2{15}-5\frac13:\frac89\right):11+1\frac34-\frac34\)
\(=\left(\frac{25}{4}\cdot\frac{32}{15}-\frac{16}{3}\cdot\frac98\right):11+1\)
\(=\left(\frac{40}{3}-6\right):11+1=\frac6{11}+1=\frac{17}{11}.\)
\((2\frac12+3\frac13):(2\frac12-1\frac13):((4\frac35+2\frac13):(4\frac35-2\frac13))\)
\(=\frac{35/6}{7/6}:\frac{104/15}{34/15}=5:\frac{52}{17}=\frac{85}{52}.\)
\(6\frac34:3+\frac{27}{40}\left((6\frac7{12}-3\frac{17}{36})\cdot2\frac12-4\frac13\cdot\frac{13}{20}\right)-1\frac14\)
\(=\frac94+\frac{27}{40}\left(\frac{61}{18}\cdot\frac52-\frac{13}{3}\cdot\frac{13}{20}\right)-\frac54\)
\(=1+\frac{27}{40}\left(\frac{305}{36}-\frac{169}{60}\right)=1+\frac{27}{40}\cdot\frac{113}{18}=\frac{679}{160}.\)
Ответ: а) 121/42; б) 17/11; в) 85/52; г) 679/160.