2) x^2 - 3x + √5-x = √5-x + 18

Subtracting √5-x from both sides gives x^2 - 3x = 18. Rearranging to a quadratic equation: x^2 - 3x - 18 = 0. Factoring the quadratic: (x-6)(x+3) = 0. The solutions are x=6 and x=-3. We must check for extraneous solutions due to the square root. For x=6, √5-6 is undefined. For x=-3, √5-(-3) = √8, which is valid. Thus, the only solution is x = -3.