2. Вычислите: а) (6 − 3 5/12) − (3 − 1 1/12); в) (7 − 3 7/11) − (4 − 2 8/11).

а)

\(3\frac{5}{12}=\frac{41}{12}\), \(1\frac{1}{12}=\frac{13}{12}\).

\((6-3\frac{5}{12})-(3-1\frac{1}{12})=(\frac{72}{12}-\frac{41}{12})-(\frac{36}{12}-\frac{13}{12})=\frac{31}{12}-\frac{23}{12}=\frac{8}{12}=\frac{2}{3}\).

в)

\(3\frac{7}{11}=\frac{40}{11}\), \(2\frac{8}{11}=\frac{30}{11}\).

\((7-3\frac{7}{11})-(4-2\frac{8}{11})=(\frac{77}{11}-\frac{40}{11})-(\frac{44}{11}-\frac{30}{11})=\frac{37}{11}-\frac{14}{11}=\frac{23}{11}=2\frac{1}{11}\).

Ответ: а) \(\frac{2}{3}\); в) \(2\frac{1}{11}\).