Ответ:
Приведём дробные части к общему знаменателю и сложим целые и дробные части.
- \(38\frac{1}{8}+4\frac{5}{24}=42+\left(\frac{3}{24}+\frac{5}{24}\right)=42\frac{8}{24}=42\frac{1}{3}\).
- \(4\frac{19}{75}+6\frac{17}{45}=10+\left(\frac{57}{225}+\frac{85}{225}\right)=10\frac{142}{225}\).
- \(47\frac{3}{14}+1\frac{8}{21}=48+\left(\frac{9}{42}+\frac{16}{42}\right)=48\frac{25}{42}\).
- \(54\frac{3}{4}+18\frac{5}{6}=72+\left(\frac{9}{12}+\frac{10}{12}\right)=72\frac{19}{12}=73\frac{7}{12}\).
- \(28\frac{5}{9}+13\frac{3}{4}=41+\left(\frac{20}{36}+\frac{27}{36}\right)=41\frac{47}{36}=42\frac{11}{36}\).
- \(\frac{4}{7}+2\frac{3}{5}=2+\left(\frac{20}{35}+\frac{21}{35}\right)=2\frac{41}{35}=3\frac{6}{35}\).
- \(9+2\frac{2}{9}=11\frac{2}{9}\).
- \(3\frac{11}{24}+\frac{1}{6}=3+\left(\frac{11}{24}+\frac{4}{24}\right)=3\frac{15}{24}=3\frac{5}{8}\).
Ответ: а) \(42\frac{1}{3}\); б) \(10\frac{142}{225}\); в) \(48\frac{25}{42}\); г) \(73\frac{7}{12}\); д) \(42\frac{11}{36}\); е) \(3\frac{6}{35}\); ж) \(11\frac{2}{9}\); з) \(3\frac{5}{8}\).
