Решение:
- \( -z \cdot 5 = -150 \)
\( -5z = -150 \)
\( z = \frac{-150}{-5} \)
\( z = 30 \) - \( 4 \cdot \left(-z\right) = -32 \)
\( -4z = -32 \)
\( z = \frac{-32}{-4} \)
\( z = 8 \) - \( -0,4y = 44 \)
\( y = \frac{44}{-0,4} \)
\( y = -110 \) - \( \frac{1}{7} z = -1 \)
\( z = -1 \cdot 7 \)
\( z = -7 \)
Ответ: а) z = 30; б) z = 8; в) y = -110; г) z = -7.