133. Решите уравнение: а) \(x+\frac{7}{12}=\frac{17}{20}\); б) \(\frac{11}{25}+m=\frac{19}{30}\); в) \(\frac{5}{6}-n=\frac{3}{8}\); г) \(y-\frac{7}{24}=\frac{5}{9}+\frac{1}{12}\).

1. а) \(x=\frac{17}{20}-\frac{7}{12}=\frac{51}{60}-\frac{35}{60}=\frac{16}{60}=\frac{4}{15}\).
2. б) \(m=\frac{19}{30}-\frac{11}{25}=\frac{95}{150}-\frac{66}{150}=\frac{29}{150}\).
3. в) \(n=\frac{5}{6}-\frac{3}{8}=\frac{20}{24}-\frac{9}{24}=\frac{11}{24}\).
4. г) \(y=\frac{5}{9}+\frac{1}{12}+\frac{7}{24}=\frac{20}{36}+\frac{3}{36}+\frac{21}{72}=\frac{46}{72}+\frac{21}{72}=\frac{67}{72}\).

Ответ: а) \(x=\frac{4}{15}\); б) \(m=\frac{29}{150}\); в) \(n=\frac{11}{24}\); г) \(y=\frac{67}{72}\).