Вопрос:

119. Произвести указанные действия: 1) \(10\frac{5}{6}+(5\frac{1}{3}-2\frac{1}{6})\); 2) \(4\frac{5}{12}+13\frac{4}{5}-5\frac{5}{6}\); 3) \(12\frac{3}{4}-6\frac{7}{8}+4\frac{1}{2}-1\frac{2}{3}\); 4) \(\frac{13}{84}-\frac{4}{35}+\frac{11}{70}-\frac{7}{60}\); 5) \((\frac{11}{15}-\frac{3}{10})+(\frac{7}{25}-\frac{3}{100})\); 6) \((\frac{13}{18}-\frac{5}{36})+(\frac{29}{72}-\frac{1}{24})\).

Ответ:

  1. \(10\frac{5}{6}+\left(5\frac{1}{3}-2\frac{1}{6}\right)=10\frac{5}{6}+3\frac{1}{6}=14\).
  2. \(4\frac{5}{12}+13\frac{4}{5}-5\frac{5}{6}=\frac{53}{12}+\frac{69}{5}-\frac{35}{6}=\frac{265+828-350}{60}=\frac{743}{60}=12\frac{23}{60}\).
  3. \(12\frac{3}{4}-6\frac{7}{8}+4\frac{1}{2}-1\frac{2}{3}=\frac{51}{4}-\frac{55}{8}+\frac{9}{2}-\frac{5}{3}=\frac{306-165+108-40}{24}=\frac{209}{24}=8\frac{17}{24}\).
  4. \(\frac{13}{84}-\frac{4}{35}+\frac{11}{70}-\frac{7}{60}=\frac{65-48+66-49}{420}=\frac{34}{420}=\frac{17}{210}\).
  5. \(\left(\frac{11}{15}-\frac{3}{10}\right)+\left(\frac{7}{25}-\frac{3}{100}\right)=\left(\frac{22}{30}-\frac{9}{30}\right)+\left(\frac{28}{100}-\frac{3}{100}\right)=\frac{13}{30}+\frac{1}{4}=\frac{67}{60}=1\frac{7}{60}\).
  6. \(\left(\frac{13}{18}-\frac{5}{36}\right)+\left(\frac{29}{72}-\frac{1}{24}\right)=\left(\frac{26}{36}-\frac{5}{36}\right)+\left(\frac{29}{72}-\frac{3}{72}\right)=\frac{7}{12}+\frac{13}{36}=\frac{21+13}{36}=\frac{17}{18}\).

Ответ: 1) \(14\); 2) \(12\frac{23}{60}\); 3) \(8\frac{17}{24}\); 4) \(\frac{17}{210}\); 5) \(1\frac{7}{60}\); 6) \(\frac{17}{18}\).