Решение:
- a) 3 \( \frac{5}{8} \) + 5 \( \frac{7}{8} \)
\( 3 \frac{5}{8} + 5 \frac{7}{8} = (3+5) + (\frac{5}{8} + \frac{7}{8}) = 8 + \frac{12}{8} = 8 + 1 \frac{4}{8} = 9 \frac{1}{2} \) - б) 6 \( \frac{2}{14} \) - \( \frac{13}{14} \)
\( 6 \frac{2}{14} - \frac{13}{14} = 5 + 1 + \frac{2}{14} - \frac{13}{14} = 5 + \frac{14}{14} + \frac{2}{14} - \frac{13}{14} = 5 + \frac{16}{14} - \frac{13}{14} = 5 \frac{3}{14} \) - д) 1 \( \frac{8}{10} \) + 2 \( \frac{1}{7} \) + \( \frac{2}{10} \) + 3 \( \frac{6}{7} \)
\( 1 \frac{8}{10} + 2 \frac{1}{7} + \frac{2}{10} + 3 \frac{6}{7} = (1+2+3) + (\frac{8}{10} + \frac{2}{10}) + (\frac{1}{7} + \frac{6}{7}) = 6 + \frac{10}{10} + \frac{7}{7} = 6 + 1 + 1 = 8 \) - е) 3 \( \frac{1}{4} \) - (\( \frac{1}{7} \) + 1 \( \frac{1}{4} \))
\( 3 \frac{1}{4} - (\frac{1}{7} + 1 \frac{1}{4}) = 3 \frac{1}{4} - \frac{1}{7} - 1 \frac{1}{4} = (3 - 1) + (\frac{1}{4} - \frac{1}{4}) - \frac{1}{7} = 2 - \frac{1}{7} = 1 \frac{6}{7} \) - B) 4 \( \frac{6}{25} \) - 4 \( \frac{6}{25} \)
\( 4 \frac{6}{25} - 4 \frac{6}{25} = 0 \) - г) 2 \( \frac{5}{9} \) - 0
\( 2 \frac{5}{9} - 0 = 2 \frac{5}{9} \)
Ответ: а) \( 9 \frac{1}{2} \); б) \( 5 \frac{3}{14} \); д) 8; е) \( 1 \frac{6}{7} \); B) 0; г) \( 2 \frac{5}{9} \).