1. Решите уравнение: a) 8y = -624+5y б) \(\(\frac{3}{4}\)x + 1 = \(\frac{2}{6}\)x + \(\frac{1}{3}\) в) 5x +6 =4x +10

Решение:

1. а)
   

   8y = -624 + 5y

   
   

   8y - 5y = -624

   
   

   3y = -624

   
   

   y = \(\frac{-624}{3}\)

   
   

   y = -208

2. б)
   

   \(\frac{3}{4}x + 1 = \frac{2}{6}x + \frac{1}{3}\)

   
   

   \(\frac{3}{4}x - \frac{1}{3}x = \frac{1}{3} - 1\)

   
   

   \(\frac{9x - 4x}{12} = \frac{1-3}{3}\)

   
   

   \(\frac{5x}{12} = \frac{-2}{3}\)

   
   

   5x = \(\frac{-2 \times 12}{3}\)

   
   

   5x = -8

   
   

   x = \(\frac{-8}{5}\)

   
   

   x = -1.6

3. в)
   

   5x + 6 = 4x + 10

   
   

   5x - 4x = 10 - 6

   
   

   x = 4

Ответ: а) y = -208; б) x = -1.6; в) x = 4