Ответ:
Решение:
Чтобы представить неправильную дробь в виде целого или смешанного числа, нужно числитель разделить на знаменатель. Целая часть — это результат деления, а остаток от деления будет числителем новой дроби, знаменатель остается прежним.
- \(\frac{7}{3}\) = \(2\frac{1}{3}\)
- \(\frac{44}{11}\) = \(4\)
- \(\frac{19}{7}\) = \(2\frac{5}{7}\)
- \(\frac{68}{9}\) = \(7\frac{5}{9}\)
- \(\frac{25}{4}\) = \(6\frac{1}{4}\)
- \(\frac{9}{5}\) = \(1\frac{4}{5}\)
- \(\frac{90}{9}\) = \(10\)
- \(\frac{12}{5}\) = \(2\frac{2}{5}\)
- \(\frac{35}{6}\) = \(5\frac{5}{6}\)
- \(\frac{8}{3}\) = \(2\frac{2}{3}\)
- \(\frac{51}{5}\) = \(10\frac{1}{5}\)
- \(\frac{26}{13}\) = \(2\)
- \(\frac{15}{3}\) = \(5\)
- \(\frac{17}{5}\) = \(3\frac{2}{5}\)
- \(\frac{40}{5}\) = \(8\)
- \(\frac{47}{6}\) = \(7\frac{5}{6}\)
- \(\frac{25}{5}\) = \(5\)
- \(\frac{60}{12}\) = \(5\)
- \(\frac{29}{18}\) = \(1\frac{11}{18}\)
- \(\frac{75}{8}\) = \(9\frac{3}{8}\)
- \(\frac{55}{4}\) = \(13\frac{3}{4}\)
- \(\frac{13}{4}\) = \(3\frac{1}{4}\)
- \(\frac{63}{4}\) = \(15\frac{3}{4}\)
- \(\frac{98}{9}\) = \(10\frac{8}{9}\)
- \(\frac{10}{3}\) = \(3\frac{1}{3}\)
- \(\frac{40}{17}\) = \(2\frac{6}{17}\)
- \(\frac{53}{6}\) = \(8\frac{5}{6}\)
- \(\frac{49}{9}\) = \(5\frac{4}{9}\)
