Вопрос:
1.3. Действия с обыкновенными дробями
14. Выполните сложение или вычитание.
Ответ:
Решение:
- \( \frac{1}{2} + \frac{3}{8} = \frac{4}{8} + \frac{3}{8} = \frac{7}{8} \)
- \( \frac{2}{7} + \frac{5}{14} = \frac{4}{14} + \frac{5}{14} = \frac{9}{14} \)
- \( \frac{3}{5} + \frac{4}{15} = \frac{9}{15} + \frac{4}{15} = \frac{13}{15} \)
- \( \frac{1}{8} + \frac{3}{16} = \frac{2}{16} + \frac{3}{16} = \frac{5}{16} \)
- \( \frac{2}{9} + \frac{5}{18} = \frac{4}{18} + \frac{5}{18} = \frac{9}{18} = \frac{1}{2} \)
- \( \frac{8}{13} - \frac{1}{26} = \frac{16}{26} - \frac{1}{26} = \frac{15}{26} \)
- \( \frac{7}{15} - \frac{7}{30} = \frac{14}{30} - \frac{7}{30} = \frac{7}{30} \)
- \( \frac{2}{19} - \frac{1}{38} = \frac{4}{38} - \frac{1}{38} = \frac{3}{38} \)
- \( \frac{5}{7} - \frac{3}{14} = \frac{10}{14} - \frac{3}{14} = \frac{7}{14} = \frac{1}{2} \)
- \( \frac{4}{21} - \frac{1}{7} = \frac{4}{21} - \frac{3}{21} = \frac{1}{21} \)
- \( \frac{7}{20} + \frac{11}{50} = \frac{35}{100} + \frac{22}{100} = \frac{57}{100} \)
- \( \frac{5}{9} - \frac{1}{3} = \frac{5}{9} - \frac{3}{9} = \frac{2}{9} \)
- \( \frac{11}{40} + \frac{17}{120} = \frac{33}{120} + \frac{17}{120} = \frac{50}{120} = \frac{5}{12} \)
- \( \frac{17}{33} - \frac{5}{22} = \frac{34}{66} - \frac{15}{66} = \frac{19}{66} \)
- \( \frac{27}{76} - 0 = \frac{27}{76} \)
- \( \frac{9}{20} + \frac{5}{8} = \frac{18}{40} + \frac{25}{40} = \frac{43}{40} = 1 \frac{3}{40} \)
- \( \frac{2}{7} + \frac{13}{28} = \frac{8}{28} + \frac{13}{28} = \frac{21}{28} = \frac{3}{4} \)
- \( \frac{5}{13} - \frac{14}{39} = \frac{15}{39} - \frac{14}{39} = \frac{1}{39} \)
- \( \frac{5}{8} - \frac{2}{7} = \frac{35}{56} - \frac{16}{56} = \frac{19}{56} \)
- \( \frac{3}{4} + \frac{5}{12} = \frac{9}{12} + \frac{5}{12} = \frac{14}{12} = \frac{7}{6} = 1 \frac{1}{6} \)
- \( \frac{15}{23} - \frac{27}{46} = \frac{30}{46} - \frac{27}{46} = \frac{3}{46} \)
- \( \frac{9}{25} - \frac{14}{117} = \frac{9 # 117}{25 # 117} - \frac{14 # 25}{117 # 25} = \frac{1053}{2925} - \frac{350}{2925} = \frac{703}{2925} \)
- \( \frac{17}{35} - \frac{13}{28} = \frac{68}{140} - \frac{65}{140} = \frac{3}{140} \)
- \( 1 - \frac{2}{7} = \frac{7}{7} - \frac{2}{7} = \frac{5}{7} \)
- \( \frac{13}{40} - \frac{11}{60} = \frac{39}{120} - \frac{22}{120} = \frac{17}{120} \)
- \( \frac{5}{12} + \frac{3}{4} = \frac{5}{12} + \frac{9}{12} = \frac{14}{12} = \frac{7}{6} = 1 \frac{1}{6} \)
- \( 1\frac{17}{33} + \frac{5}{22} = 1 + \frac{34}{66} + \frac{15}{66} = 1 + \frac{49}{66} = 1\frac{49}{66} \)
- \( 1\frac{5}{12} - \frac{7}{10} = 1\frac{25}{60} - \frac{42}{60} = \frac{85}{60} - \frac{42}{60} = \frac{43}{60} \)
- \( 7\frac{7}{8} - \frac{9}{10} = 7\frac{35}{40} - \frac{36}{40} = 6\frac{75}{40} - \frac{36}{40} = 6\frac{39}{40} \)
- \( 12\frac{3}{10} - 5\frac{11}{15} = 12\frac{9}{30} - 5\frac{22}{30} = 11\frac{39}{30} - 5\frac{22}{30} = 6\frac{17}{30} \)
- \( 7\frac{7}{15} - 1\frac{3}{20} = 7\frac{28}{60} - 1\frac{9}{60} = 6\frac{19}{60} \)
- \( 5\frac{1}{9} + 3\frac{2}{5} = 5\frac{5}{45} + 3\frac{18}{45} = 8\frac{23}{45} \)
- \( 3\frac{3}{8} + 1\frac{5}{12} = 3\frac{9}{24} + 1\frac{10}{24} = 4\frac{19}{24} \)
- \( 62\frac{2}{3} - 3\frac{5}{8} = 62\frac{16}{24} - 3\frac{15}{24} = 59\frac{1}{24} \)
- \( 12 - 10\frac{7}{9} = 11\frac{9}{9} - 10\frac{7}{9} = 1\frac{2}{9} \)
- \( 18 - 11\frac{8}{13} = 17\frac{13}{13} - 11\frac{8}{13} = 6\frac{5}{13} \)
- \( 15\frac{3}{17} - 4 = 11\frac{3}{17} \)
- \( 2\frac{1}{3} - \frac{4}{5} = 2\frac{5}{15} - \frac{12}{15} = \frac{35}{15} - \frac{12}{15} = \frac{23}{15} = 1\frac{8}{15} \)
- \( 16\frac{1}{4} + \frac{5}{8} = 16\frac{2}{8} + \frac{5}{8} = 16\frac{7}{8} \)