Вопрос:

1) \((2\frac{3}{17}+1\frac{1}{34})\cdot17\); 2) \((1\frac{1}{4}-\frac{3}{19})\cdot19\); 3) \(4\frac{3}{8}:(\frac{3}{8}+1\frac{4}{13})\); 4) \(5\frac{2}{5}:(3\frac{1}{4}-2\frac{4}{5})\).

Ответ:

  1. Преобразуем смешанные числа:

    \(2\frac{3}{17}=\frac{37}{17}=\frac{74}{34}\), \(1\frac{1}{34}=\frac{35}{34}\).

    \((\frac{74}{34}+\frac{35}{34})\cdot17=\frac{109}{34}\cdot17=\frac{109}{2}=54\frac{1}{2}\).

  2. \(1\frac{1}{4}=\frac{5}{4}\).

    \((\frac{5}{4}-\frac{3}{19})\cdot19=\frac{83}{76}\cdot19=\frac{83}{4}=20\frac{3}{4}\).

  3. Преобразуем смешанные числа:

    \(4\frac{3}{8}=\frac{35}{8}\), \(1\frac{4}{13}=\frac{17}{13}\).

    \(\frac{35}{8}: (\frac{3}{8}+\frac{17}{13})=\frac{35}{8}:\frac{175}{104}=\frac{35}{8}\cdot\frac{104}{175}=\frac{13}{5}=2\frac{3}{5}\).

  4. Преобразуем смешанные числа:

    \(5\frac{2}{5}=\frac{27}{5}\), \(3\frac{1}{4}=\frac{13}{4}\), \(2\frac{4}{5}=\frac{14}{5}\).

    \(\frac{27}{5}: (\frac{13}{4}-\frac{14}{5})=\frac{27}{5}:\frac{9}{20}=\frac{27}{5}\cdot\frac{20}{9}=12\).

Ответ: 1) \(54\frac{1}{2}\); 2) \(20\frac{3}{4}\); 3) \(2\frac{3}{5}\); 4) \(12\).