1.1. Вычислите: 1) \(\left(\frac{2}{47}-\frac{3}{53}\right):0,2\); 2) \(\frac{1-10^{-4}}{99}:\frac{0,16}{25}\); 3) \(0,3^4-0,08^2-\frac{1}{125}+\frac{3}{25}-\frac{3}{5}+1\).

1. \[\left(\frac{2}{47}-\frac{3}{53}\right):0,2=\left(\frac{106-141}{2491}\right):\frac{1}{5}=\frac{-35}{2491}\cdot5=-\frac{175}{2491}.\]
2. \[\frac{1-10^{-4}}{99}:\frac{0,16}{25}=\frac{1-\frac{1}{10000}}{99}:\frac{16}{100}\cdot\frac{25}{1}=\frac{\frac{9999}{10000}}{99}\cdot\frac{25}{16}=\frac{101}{6400}.\]
3. \[0,3^4-0,08^2-\frac{1}{125}+\frac{3}{25}-\frac{3}{5}+1=0,0081-0,0064-0,008+0,12-0,6+1=0,5137.\]

Ответ: 1) \(-\frac{175}{2491}\); 2) \(\frac{101}{6400}\); 3) \(0,5137\).