1. $(1\frac{3}{5}+2\frac{1}{5}):1,9\times(1,7-\frac{4}{5}):\frac{3}{7}$.

Question

$Фото задания: 1. $(1\frac{3}{5}+2\frac{1}{5}):1,9\times(1,7-\frac{4}{5}):\frac{3}{7}$.$ Фото задания

Accepted Answer

Вычислим по порядку:

$1\frac{3}{5}+2\frac{1}{5}=3\frac{4}{5}=\frac{19}{5}$.

$1,7-\frac{4}{5}=\frac{17}{10}-\frac{8}{10}=\frac{9}{10}$.

$\frac{19}{5}:1,9\times\frac{9}{10}:\frac{3}{7}=\frac{19}{5}:\frac{19}{10}\times\frac{9}{10}:\frac{3}{7}$.

$=2\times\frac{9}{10}\times\frac{7}{3}=\frac{21}{5}=4\frac{1}{5}$.

Ответ: $4\frac{1}{5}$.

1. \((1\frac{3}{5}+2\frac{1}{5}):1,9\times(1,7-\frac{4}{5}):\frac{3}{7}\).