№2. Вычислите: a)1+(3/8)^2:1 1/2 б) 9+(2/7)^2:1 5/7 B)3 1/4-24/5+4 1/2:15/12⋅6

Ответ:

1. \(1+\left(\frac{3}{8}\right)^2:\frac{3}{2}=1+\frac{9}{64}:\frac{3}{2}=1+\frac{9}{64}\cdot\frac{2}{3}=1+\frac{3}{32}=1\frac{3}{32}\)
2. \(9+\left(\frac{2}{7}\right)^2:\frac{12}{7}=9+\frac{4}{49}:\frac{12}{7}=9+\frac{4}{49}\cdot\frac{7}{12}=9+\frac{1}{21}=9\frac{1}{21}\)
3. \(3\frac{1}{4}-\frac{24}{5}+4\frac{1}{2}:\frac{15}{12}\cdot6=\frac{13}{4}-\frac{24}{5}+\frac{9}{2}:\frac{5}{4}\cdot6=\frac{13}{4}-\frac{24}{5}+\frac{9}{2}\cdot\frac{4}{5}\cdot6=\frac{13}{4}-\frac{24}{5}+\frac{108}{5}=\frac{65-96+432}{20}=\frac{401}{20}=20\frac{1}{20}\)

Ответ: \(1\frac{3}{32}\); \(9\frac{1}{21}\); \(20\frac{1}{20}\).