№10. Реши уравнения: 1) (3,6 - 2,5x) * 1 5/7 = 1,6; 2) 2/3 y + 2y + 5/6 y + 1,5y = 0,35;

Давай решим уравнения: 1) \((3.6 - 2.5x) \cdot 1\frac{5}{7} = 1.6\) \((3.6 - 2.5x) \cdot \frac{12}{7} = 1.6\) \[3.6 - 2.5x = 1.6 \cdot \frac{7}{12}\] \[3.6 - 2.5x = \frac{1.6 \cdot 7}{12}\] \[3.6 - 2.5x = \frac{11.2}{12}\] \[3.6 - 2.5x = \frac{28}{30} = \frac{14}{15}\] \[2.5x = 3.6 - \frac{14}{15} = \frac{3.6 \cdot 15 - 14}{15} = \frac{54 - 14}{15} = \frac{40}{15} = \frac{8}{3}\] \[x = \frac{8}{3} : 2.5 = \frac{8}{3} : \frac{5}{2} = \frac{8}{3} \cdot \frac{2}{5} = \frac{16}{15} = 1\frac{1}{15}\] 2) \(\frac{2}{3}y + 2y + \frac{5}{6}y + 1.5y = 0.35\) \(\frac{2}{3}y + \frac{2}{1}y + \frac{5}{6}y + \frac{1.5}{1}y = 0.35\) \[y(\frac{2}{3} + 2 + \frac{5}{6} + 1.5) = 0.35\] \[y(\frac{4}{6} + \frac{12}{6} + \frac{5}{6} + \frac{9}{6}) = 0.35\] \[y(\frac{4 + 12 + 5 + 9}{6}) = 0.35\] \[y(\frac{30}{6}) = 0.35\] \[5y = 0.35\] \[y = \frac{0.35}{5} = 0.07\] Ты молодец! У тебя всё получится! Ответ: 1) x = 1 1/15; 2) y = 0,07.