Решения заданий Вариант 2:
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$$y = x^6 - 7x$$
$$y' = 6x^5 - 7$$
Ответ: $$y' = 6x^5 - 7$$
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$$y = 6x^4 + 9x^3 - 10$$
$$y' = 24x^3 + 27x^2$$
Ответ: $$y' = 24x^3 + 27x^2$$
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$$y = \sqrt{x} - 15x$$
$$y = x^{\frac{1}{2}} - 15x$$
$$y' = \frac{1}{2}x^{-\frac{1}{2}} - 15$$
$$y' = \frac{1}{2\sqrt{x}} - 15$$
Ответ: $$y' = \frac{1}{2\sqrt{x}} - 15$$
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$$y = 5x^{-2} - \frac{1}{x} + 9$$
$$y = 5x^{-2} - x^{-1} + 9$$
$$y' = -10x^{-3} + x^{-2}$$
$$y' = -\frac{10}{x^3} + \frac{1}{x^2}$$
Ответ: $$y' = -\frac{10}{x^3} + \frac{1}{x^2}$$
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$$y = \frac{4}{x^5} - tgx$$
$$y = 4x^{-5} - tgx$$
$$y' = -20x^{-6} - \frac{1}{cos^2x}$$
$$y' = -\frac{20}{x^6} - \frac{1}{cos^2x}$$
Ответ: $$y' = -\frac{20}{x^6} - \frac{1}{cos^2x}$$
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$$y = 5sinx + \sqrt{x}$$
$$y = 5sinx + x^{\frac{1}{2}}$$
$$y' = 5cosx + \frac{1}{2}x^{-\frac{1}{2}}$$
$$y' = 5cosx + \frac{1}{2\sqrt{x}}$$
Ответ: $$y' = 5cosx + \frac{1}{2\sqrt{x}}$$
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$$y = \frac{6}{x^{-3}} - cosx$$
$$y = 6x^3 - cosx$$
$$y' = 18x^2 + sinx$$
Ответ: $$y' = 18x^2 + sinx$$
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$$y = (x^6 + 3)(x^4 - 4)$$
$$y = x^{10} - 4x^6 + 3x^4 - 12$$
$$y' = 10x^9 - 24x^5 + 12x^3$$
Ответ: $$y' = 10x^9 - 24x^5 + 12x^3$$
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$$y = \sqrt{x}(6x - 1)$$
$$y = 6x^{\frac{3}{2}} - x^{\frac{1}{2}}$$
$$y' = 9x^{\frac{1}{2}} - \frac{1}{2}x^{-\frac{1}{2}}$$
$$y' = 9\sqrt{x} - \frac{1}{2\sqrt{x}}$$
Ответ: $$y' = 9\sqrt{x} - \frac{1}{2\sqrt{x}}$$
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$$y = x^6 cosx$$
$$y' = 6x^5 cosx - x^6 sinx$$
Ответ: $$y' = 6x^5 cosx - x^6 sinx$$
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$$y = (\frac{3}{x} - 4)(3x + 6)$$
$$y = (3x^{-1} - 4)(3x + 6)$$
$$y = 9 - 12x - 18x^{-1}$$
$$y' = -12 + 18x^{-2}$$
$$y' = -12 + \frac{18}{x^2}$$
Ответ: $$y' = -12 + \frac{18}{x^2}$$
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$$y = \frac{4x^5}{2x + 5}$$
$$y' = \frac{20x^4(2x + 5) - 4x^5 \cdot 2}{(2x + 5)^2}$$
$$y' = \frac{40x^5 + 100x^4 - 8x^5}{(2x + 5)^2}$$
$$y' = \frac{32x^5 + 100x^4}{(2x + 5)^2}$$
$$y' = \frac{4x^4(8x + 25)}{(2x + 5)^2}$$
Ответ: $$y' = \frac{4x^4(8x + 25)}{(2x + 5)^2}$$
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$$y = \frac{9\sqrt{x}}{6 + 2x^5}$$
$$y = \frac{9x^{\frac{1}{2}}}{6 + 2x^5}$$
$$y' = \frac{\frac{9}{2}x^{-\frac{1}{2}}(6 + 2x^5) - 9x^{\frac{1}{2}} \cdot 10x^4}{(6 + 2x^5)^2}$$
$$y' = \frac{\frac{27}{\sqrt{x}} + 9x^{\frac{9}{2}} - 90x^{\frac{9}{2}}}{(6 + 2x^5)^2}$$
$$y' = \frac{\frac{27}{\sqrt{x}} - 81x^{\frac{9}{2}}}{(6 + 2x^5)^2}$$
$$y' = \frac{\frac{27 - 81x^5}{\sqrt{x}}}{(6 + 2x^5)^2}$$
$$y' = \frac{27 - 81x^5}{\sqrt{x}(6 + 2x^5)^2}$$
Ответ: $$y' = \frac{27 - 81x^5}{\sqrt{x}(6 + 2x^5)^2}$$
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$$y = \frac{4x}{ctgx}$$
$$y' = \frac{4ctgx - 4x(-\frac{1}{sin^2x})}{ctg^2x}$$
$$y' = \frac{4ctgx + \frac{4x}{sin^2x}}{ctg^2x}$$
$$y' = \frac{4ctgx + 4x csc^2x}{ctg^2x}$$
Ответ: $$y' = \frac{4ctgx + 4x csc^2x}{ctg^2x}$$