32. ($$\frac{2}{5}$$x²y) × (-$$\frac{5}{4}$$xy²).

$$(\frac{2}{5}x^2y) \times (-\frac{5}{4}xy^2) = \frac{2}{5} \times -\frac{5}{4} \times x^2 \times x \times y \times y^2 = -\frac{1}{2}x^3y^3$$