19) $$\frac{8}{15}$$(3$$\frac{3}{4}$$x -$$\frac{5}{16}$$y)-$$\frac{3}{20}$$(6$$\frac{2}{3}$$x-4$$\frac{4}{9}$$y) =

19) $$\frac{8}{15}$$(3$$\frac{3}{4}$$x -$$\frac{5}{16}$$y)-$$\frac{3}{20}$$(6$$\frac{2}{3}$$x-4$$\frac{4}{9}$$y) = $$\frac{8}{15}$$($$\frac{15}{4}$$x -$$\frac{5}{16}$$y)-$$\frac{3}{20}$$($$\frac{20}{3}$$x -$$\frac{40}{9}$$y) = $$\frac{8\cdot15}{15\cdot4}$$x - $$\frac{8\cdot5}{15\cdot16}$$y - $$\frac{3\cdot20}{20\cdot3}$$x + $$\frac{3\cdot40}{20\cdot9}$$y = 2x - $$\frac{1}{6}$$y - x + $$\frac{2}{3}$$y = x + $$\frac{3}{6}$$y = x + $$\frac{1}{2}$$y

Ответ: x + $$\frac{1}{2}$$y