1.008.
Решение:
$$\begin{aligned} &\frac{3\frac{1}{3}+2,5}{2,5-1\frac{2}{3}} = \frac{\frac{10}{3}+\frac{5}{2}}{\frac{5}{2}-\frac{5}{3}} = \frac{\frac{20+15}{6}}{\frac{15-10}{6}} = \frac{\frac{35}{6}}{\frac{5}{6}} = \frac{35}{6} \cdot \frac{6}{5} = 7 \end{aligned}$$ $$\begin{aligned} &\frac{4,6-2\frac{2}{3}}{4,6+2\frac{2}{3}} = \frac{\frac{46}{10}-\frac{8}{3}}{\frac{46}{10}+\frac{8}{3}} = \frac{\frac{138-80}{30}}{\frac{138+80}{30}} = \frac{58}{218} = \frac{29}{109} \approx 0,27 \end{aligned}$$ $$\begin{aligned} &5,2 = \frac{52}{10} = \frac{26}{5} = 5\frac{1}{5} \end{aligned}$$ $$\begin{aligned} &\frac{0,05}{7}-0,125 = \frac{5}{700}-\frac{125}{1000} = \frac{1}{140} - \frac{1}{8} = \frac{2-35}{280} = \frac{-33}{280} \approx -0,12 \end{aligned}$$Ответ: \(\frac{3\frac{1}{3}+2,5}{2,5-1\frac{2}{3}} = 7\), \(\frac{4,6-2\frac{2}{3}}{4,6+2\frac{2}{3}} \approx 0,27\), \(5,2 = 5\frac{1}{5}\), \(\frac{0,05}{7}-0,125 \approx -0,12\)